a, -150(1352-41) / (1352-41)(150-15) <x< (2400:48)-250 / 350 - (3600:12)
b, 10,07 - [ 3,927 - ( 3,63 - 3/20) ] < hoặc bằng x < hoặc bằng 1,5. (9,2-2/5) + (3,2-3,12) (41/10 -2,85 )
tim x thuocZ :-150(1352-41) / (1352-41)(150-15) < x < (2400:48)-250 / 350-(3600-12)
\(\frac{-150.\left(1352-41\right)}{\left(1352-41\right).\left(150-15\right)}< x< \frac{\left(2400:48\right)-250}{350-\left(3600:12\right)}\)
\(\frac{-150.\left(1352-41\right)}{\left(1352-41\right)\left(150-15\right)}< x< \frac{2400:48-250}{350-3600:12}\)
tìm x thuộc Z
Rút gọn:
a,\(\frac{15.\left(1352-41\right)}{\left(1352-41\right)\left(150-15\right)}\)
b,\(\frac{2^{10}.6^{15}+3^{14}.15.4^{13}}{2^{18}.18^7.3^3+3^{15}.2^{25}}\)
Cần gấp ạ
Tính hợp lý:
A) 420 - ( 71+420)
b) ( 35 - 120 ) + ( 120+410-35)
c) (320 - 15 + 49) - ( 85 - 51)
d) -(312 + 59) - (41 + 400 + 88)
e) (430 - 731) - ( -731 + 430 - 56)
f) (1352 - 47) - ( 53 -1000+ 1352)
h) (-42) - (370 + 58) - ( 120 -370)
a) $420-(71+420)$
$=420-71-420$
$=-71$
b) $(35-120)+(120+410-35)$
$=35-120+120+410-35$
$=(35-35)+(-120+120)+410$
$=410$
c) $(320-15+49)-(85-51)$
$=320-15+49-85+51$
$=320+(-15-85)+(49+51)$
$=320+(-100)+100$
$=320$
d) $-(312+59)-(41+400+88)$
$=-312-59-41-400-88$
$=(-312-88)+(-59-41)-400$
$=-400+(-100)-400$
$=-500-400$
$=-900$
e) $(430-731)-(-731+430-56)$
$=430-731+731-430+56$
$=(430-430)+(-731+731)+56$
$=56$
f) $(1352-47)-(53-1000+1352)$
$=1352-47-53+1000-1352$
$=(1352-1352)+(-47-53)+1000$
$=(-100)+1000$
$=1000-100$
$=900$
h) $(-42)-(370+58)-(120-370)$
$=-42-370-58-120+370$
$=(-42-58)+(-370+370)-120$
$=-100-120$
$=-220$
$Toru$
Tìm số nguyên x biết:
a)\(\frac{-150\left(1352-41\right)}{\left(1352-41\right)\left(50-45\right)}\)<x<\(\frac{\left(2400:48\right)-250}{350-\left(3600:12\right)}\)
b)10,07-[3,927-(3,63-\(\frac{3}{20}\))\(\le\)x\(\le\)1,5 \(\left(9,2-\frac{2}{5}\right)\)+(3,2-3,12).(\(4\frac{1}{10}\)-2,25)
13246 / x = 1352
\(a,\frac{-5}{14}-\frac{37}{14}\le x
một phép chia có số chia là 26,số dư là 15.Tổng số bị chia,số chia,thương và số dư là 1352.tìm số bị chia và số thương.